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Motion In A Plane

Question
CBSEENPH11018072

If space space straight R with rightwards arrow on top equals straight A with rightwards arrow on top plus straight B with rightwards arrow on top  and open vertical bar straight R with rightwards arrow on top close vertical bar space equals space open vertical bar straight A with rightwards arrow on top close vertical bar space equals space open vertical bar straight B with rightwards arrow on top close vertical bar then what is the angle between straight A with rightwards arrow on top space and space straight B with rightwards arrow on top ?

Solution

Let straight theta be the angle between straight A with rightwards arrow on top space and space straight B with rightwards arrow on top. 
∴ Resultant is given by,
open vertical bar straight R with rightwards arrow on top close vertical bar space equals space open vertical bar straight A with rightwards arrow on top plus straight B with rightwards arrow on top close vertical bar space equals space square root of straight A squared plus straight B squared plus 2 AB thin space cosθ end root 
straight R squared space equals space straight A squared plus straight B squared plus 2 AB space cosθ 
Hence, R = A = B
Thus, straight A squared equals straight A squared plus straight A squared plus 2 straight A squared cosθ 
     
rightwards double arrow  cosθ equals negative 1 half
rightwards double arrow      straight theta equals 120 degree, is the required angle between them.