-->

Laws Of Motion

Question
CBSEENPH11016984

A disc is rotating with angular velocity ω about an axis passing through the centre and perpendicular to the plane of disc. A body of mass m is placed at the distance r from the centre of the disc. If the coefficient of friction between disc and body is μ then at what angular velocity will the body just slip?

Solution
Let a body of mass m be placed on the disc at a distance r from the centre.
Coefficient of friction between disc and body= μ
Therefore,
Limiting friction between body and disc = μmg.
               
Let straight omega be the angular velocity of the disc.
The body will be just at the point of slipping when centrifugal force is just equal to the force of friction.

Hence,                 m r omega to the power of italic 2 italic space italic equals italic space mu m g 
                           straight omega equals square root of μg over straight r end root, is the angular velocity when the body will just slip.