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Laws Of Motion

Question
CBSEENPH11016983

Read the following statements and pick up the true and false statements: 

(a) The net acceleration of a particle in circular motion is always along the radius of the circle towards the centre. 
(b) The change in velocity vector of a particle in uniform circular motion in one complete cycle is zero vector. 

(c) The magnitude of the change in acceleration vector in uniform circular motion over half cycle is zero.

Solution
(a) False; the statement is true if the motion is uniform circular motion. 
                         
It the speed of particle increases or decreases, then there will be tangential acceleration also. Therefore, the net acceleration will subtend some angle with the radius. 
(b) True; because in uniform circular motion the speed of particle is constant and direction of motion is given by drawing the tangent to the circle at that point.
Since after completing one cycle the particle again comes at the same point, therefore, the direction of motion and speed is same and hence the velocity is same.
Therefore, change in velocity is zero. 
                      
(c) False; the acceleration of a particle at any point is directed towards the centre at that point. 
         
At A, 
At space straight A comma space stack straight a subscript straight A with rightwards harpoon with barb upwards on top space equals space straight v squared over straight r comma space along space AO with rightwards harpoon with barb upwards on top space

At space straight B comma space straight a with rightwards harpoon with barb upwards on top subscript straight B space equals space straight v squared over straight r comma space along space BO with rightwards harpoon with barb upwards on top

Therefore space change space in space acceleration space is comma space

straight a with rightwards harpoon with barb upwards on top subscript straight B space minus space straight a with rightwards harpoon with barb upwards on top subscript straight A space equals space fraction numerator 2 straight v squared over denominator straight r end fraction comma space along space BO with rightwards harpoon with barb upwards on top space 
Hence, not zero.