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Laws Of Motion

Question
CBSEENPH11016970

Define average and instantaneous angular acceleration. Give the unit and dimensional formula of angular acceleration.

Solution
Average acceleration is the ratio of change in angular velocity of a particle to the time taken to undergo the change in angular velocity.
Let a particle be revolving with varying angular velocity.
Let at any instant t, the angular velocity of particle be straight omega and at time t+∆t, it is ω+∆ω.
Therefore average angular acceleration of particle is,
                     straight alpha subscript av equals Δω over Δt
In vector form,
                      stack straight alpha subscript av with rightwards arrow on top space equals space fraction numerator straight capital delta straight omega with rightwards arrow on top over denominator Δt end fraction
Instantaneous acceleration is the acceleration of the particle at a particular instant and is equal to limiting value of the average acceleration of particle as the time interval approaches zero. 
Mathematically, 
                   space space space space straight alpha with rightwards arrow on top space equals space limit as increment straight t rightwards arrow infinity of open parentheses fraction numerator increment straight omega with rightwards arrow on top over denominator increment straight t end fraction close parentheses equals fraction numerator dω with rightwards arrow on top over denominator dt end fraction
Also,               straight omega with rightwards arrow on top equals fraction numerator dθ with rightwards arrow on top over denominator dt end fraction   
                      alpha with italic rightwards arrow on top italic space italic equals italic space fraction numerator stack d omega with italic rightwards arrow on top over denominator d t end fraction italic equals fraction numerator d to the power of italic 2 theta with italic rightwards arrow on top over denominator d t to the power of italic 2 end fraction