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Laws Of Motion

Question
CBSEENPH11016798

A block of mass 2 kg rests on a rough inclined plane making an angle 30° with horizontal. The coefficient of friction between the block and the inclined plane is 0.65. Find the force of friction on the block.

Solution

Given,
MAss of the block, m = 2kg
Angle of inclination between the block and horizontal line is, straight theta equals 30 degree 
Coefficient of friction, straight mu equals 0.65
The force that tends to slide the body on the inclined plane is,
           straight F equals mg space sinθ
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The limiting friction between the block and the inclined plane is,
       f subscript e space equals space mu space m g space cos theta
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#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
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#6 {main}</pre>
Here, we can see that the limiting friction is greater than the force that tends to slide the body.
Therefore the body will be a rest and force of friction on the block is 9.8N