When a force of 29.4N applied on body of mass it just starts moving. Find the angle of friction. - Wired Faculty

Laws Of Motion

Question

When a force of 29.4N applied on body of mass $3 square root of 3 kg comma$ it just starts moving. Find the angle of friction.

Solution

Givem,
$Effective space force comma space straight F subscript straight e equals 29.4 straight N Mass space of space the space body comma space straight m equals 3 square root of 3 kg$
Angle of friction, $tanθ equals straight F subscript straight e over mg equals fraction numerator 29.4 over denominator 3 square root of 3 cross times 9.8 end fraction equals fraction numerator 1 over denominator square root of 3 end fraction$
$straight theta equals 30 degree$

Some More Questions From Laws of Motion Chapter

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Laws Of Motion

When a force of 29.4N applied on body of mass $3 square root of 3 kg comma$ it just starts moving. Find the angle of friction.

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