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Units And Measurement

Question
CBSEENPH11016779

What is the least count of a screw gauge, whose circular scale is divided into 100 equal parts and the pitch of the screw is 1 mm?

Solution
Number of divisions on circular scale, N = 100
Pitch of screw gauge is, d = 1 mm
space space therefore Least count = straight d over straight N 
                        equals fraction numerator 1 mm over denominator 100 end fraction equals 0.01 space mm 
                        equals space fraction numerator 1 space mm over denominator 100 end fraction equals 0.01 mm