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Laws Of Motion

Question
CBSEENPH11016748

A body exerts a force 200N normal to the rough surface having coefficient of friction 0.3. What is the value of limiting friction?

Solution

Normal force, N = 200 N

Coefficient of friction, straight mu = 0.3 
So, 
Limiting friction, FlμN space equals space 0.3 space cross times space 200 space equals space 60 space straight N