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Units And Measurement

Question
CBSEENPH11016607

Derive an expression for terminal velocity of a body of radius ‘r’ and weight W falling in a viscous media of coefficient of viscosity η. 

Solution

Let       straight v space straight alpha space straight r to the power of straight a  
          space space straight alpha space straight W to the power of straight b
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rightwards double arrow      straight nu space straight alpha space straight r to the power of straight a straight W to the power of straight b straight eta to the power of straight c
rightwards double arrow       straight v equals straight k space straight r to the power of straight a straight w to the power of straight b straight eta to the power of straight c                             ...(1)
Where k is constant of proportionality.
Substituting the dimension formula of each quantity in equation (1),
We get, 
open square brackets straight M to the power of 0 straight L to the power of 1 straight T to the power of 1 close square brackets equals open square brackets straight L close square brackets to the power of straight a open square brackets straight M to the power of 1 straight L to the power of 1 straight T to the power of negative 2 end exponent close square brackets to the power of straight b open square brackets straight M to the power of 1 straight L to the power of negative 1 end exponent straight T to the power of negative 1 end exponent close square brackets to the power of straight c 
rightwards double arrow   open square brackets straight M to the power of 0 straight L to the power of 1 straight T to the power of 1 close square brackets equals open square brackets straight M to the power of straight b plus straight c end exponent straight L to the power of straight a plus straight b minus straight c end exponent straight T to the power of negative 2 straight b minus straight c end exponent close square brackets
Equating the powers of M, L and T on both the sides, 
                   b + c = 0
rightwards double arrow          a + b - c = 1
rightwards double arrow             -2b - c = -1
On solving the above equations, we get
  a = -1,     b = 1,  c = -1
Subsituting for a, b and c  in  (1), we get
straight nu equals straight k space straight r to the power of negative 1 end exponent straight w space space space straight eta to the power of negative 1 end exponent
straight nu space equals space straight k straight omega over straight omega
 
This is the required expression for coefficient of viscosity.