A ball of mass 0.125kg moving with speed 4m/s collides the vertical wall and rebounds with same speed. What is the impulse imparted to the ball?

Solution

Mass of the ball, m = 0.125 kg
Velocity of the ball, v = 4 m/s
Initial momentum of ball is,
$straight p subscript 1 space equals m v space equals space 0.125 cross times 4 space equals space 0.5 space Ns$
After collision, the ball rebounds with the same speed. That is it is travelling in an opposite direction.
Momentum of ball after collision is,
$space straight p subscript 2 space equals space m left parenthesis negative v right parenthesis space equals 0.125 cross times left parenthesis negative 4 right parenthesis space equals negative 0.5 space Ns$
Therefore impulse of ball is
$increment straight p space equals space straight p subscript 2 minus straight p subscript 1 space equals space minus 1 space Ns$

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Laws Of Motion

A ball of mass 0.125kg moving with speed 4m/s collides the vertical wall and rebounds with same speed. What is the impulse imparted to the ball?

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