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Laws Of Motion

Question
CBSEENPH11016603

A cricket player caught a ball of mass 180 gm moving with a speed of 54 km/hr. If he took 0.08 s to catch the ball, then how much force did the player exert on the ball?

Solution

Given,
Mass of the ball, m = 180gm = 0.18kg 
Initial velocity of ball is, u = 54 km/hr = 15 m/s
Final velocity of the ball, v = 0 
∴     Impulse of the ball, I = m(u - v)
                                       = 0.18 x 15
                                       = 2.7 Ns 
Time of catching the ball, Δt space equals space 0.08 space straight s
Thus,
Force exerted by player on the ball,       straight F equals straight I over Δt equals fraction numerator 2.7 over denominator 0.08 end fraction equals 33.75 straight N