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Laws Of Motion

Question
CBSEENPH11016692

Two bodies of masses m1 and m2 are connected by a light string passing over a smooth light pulley fixed at the end of a horizontal table. The mass m1 is hanging and mass m2 lies on horizontal surface. Find the acceleration of system and tension in the string.

Solution
Let 'a' be acceleration of system and 'T' be the tension in the string. 
 
Equation of motion of mass m1 is, 
straight m subscript 1 straight g minus straight T equals straight m subscript 1 straight a                   ...(1)
Equation of motion of mass m subscript 2 is, 
T equals m subscript 2 a                        ...(2)
Adding (1) and (2), 
               m subscript 1 g equals left parenthesis m subscript 1 plus m subscript 2 right parenthesis a
                a equals fraction numerator m subscript 1 over denominator m subscript 1 plus m subscript 2 end fraction g , is the acceleration of the system.
Substituting the value of a in (2), 
Tension in the string, T equals fraction numerator m subscript 1 m subscript 2 over denominator m subscript 1 plus m subscript 2 end fraction g