-->

Laws Of Motion

Question
CBSEENPH11016535

An electron is subjected to a force 1.8 cross times 10 to the power of negative 23 end exponent straight N. How long it will travel in 1.2 ms?

Solution

Given,
Force acting on the electron, F = 1.82 space cross times space 10 to the power of negative 23 end exponent straight N
Mass of electron, 
Time of travel,  <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>
The acceleration of electron is given by, 
space space space straight a equals straight F over straight m equals fraction numerator 1.82 cross times 10 to the power of negative 23 end exponent over denominator 9.1 cross times 10 to the power of negative 31 end exponent end fraction equals 2 cross times 10 to the power of 7 straight m divided by straight s squared
Now, using the second equation of motion, 
                 space space space straight s equals ut plus 1 half at squared
We have, 
sequals space 0 cross times straight t plus 1 half left parenthesis 2 cross times 10 to the power of 7 right parenthesis space left parenthesis 1.2 cross times 10 to the power of negative 3 end exponent right parenthesis squared
  equals space 0.144 space straight m