A cracker rocket is ejecting 80gm of gases per minute at the speed of 420m/s. Find the accelerating force on the rocket.

Solution

Given,
Rate of ejection of gases,
$dm over dt equals 80 gm divided by min space space space space space space space space space equals fraction numerator 80 cross times 10 to the power of negative 3 end exponent over denominator 60 end fraction kg divided by straight s$
$space space equals 4 over 3 cross times 10 to the power of negative 3 end exponent kg divided by straight s$
Initial speed of ejection of gases from rocket, $space space u space equals space 2000 straight m divided by straight s$
∴ Accelerating force on the rocket is,
$straight F equals straight u dm over dt equals 420 cross times 4 over 3 cross times 10 to the power of negative 3 end exponent space equals space 0.56 space straight N$

Some More Questions From Laws of Motion Chapter

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Laws Of Motion

A cracker rocket is ejecting 80gm of gases per minute at the speed of 420m/s. Find the accelerating force on the rocket.

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