-->

Laws Of Motion

Question
CBSEENPH11016584

A rocket has mass 6000kg. 25% of the initial mass of the rocket is fuel. The fuel burns at the rate of 25kg/s. If the gases leave the rocket with speed 2000m/s w.r.t. rocket, then find the velocity of rocket at t = 40s. Assume the rocket takes off from rest.

Solution
The velocity of rocket at any instant
is given by,
                straight v equals straight u space Ln open parentheses fraction numerator straight m subscript straight o over denominator straight m subscript straight o minus begin display style dm over dt end style straight t end fraction close parentheses      ... (1)
Given,
Mass of rocket, straight m subscript straight o space equals space 6000
Rate of burning of fuel,  dm/dt = 25 kg/s
Speed with which the gas leaves rocket, u = 2000m/s
Time, t = 40 s
Putting the values in eqn. (1), we have 
       straight v equals 2000 cross times Ln fraction numerator 6000 over denominator 6000 minus 25 cross times 40 end fraction
         = space space 2000 cross times Ln left parenthesis 1.2 right parenthesis
         = 364.64 m/s