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Laws Of Motion

Question
CBSEENPH11016575

A shell of mass 40 kg moving with velocity 20m/s explodes and burst into two portions of masses 32kg and 8 kg. Heavier mass comes to rest after explosion. What is the energy released during the explosion?

Solution
Mass of the shell, m = 40 kg
Velocity with which the shell is moving, v = 20 m/s
Let V be the velocity of 8 kg mass after explosion.
Now using law of conservation of linear momentum.
We have, 
                 40 x 20 = 32 x 0 + 8 x V
rightwards double arrow              V = 100 m/s
Kinetic energy of shell before explosion is,
   straight K subscript 1 space equals space 1 half cross times 40 cross times left parenthesis 20 right parenthesis squared space equals space 8000 straight J       
Kinetic energy of shell after explosion is, 
    straight K subscript 2 space equals space 1 half cross times 32 cross times left parenthesis 0 right parenthesis squared plus 1 half cross times 8 cross times left parenthesis 100 right parenthesis squared      
         = 0 + 40000
         = 40000J

Thus, amount of energy released is,
           straight K subscript 2 minus straight K subscript 1 space equals space 40000 minus 8000 space equals space 32000 straight J