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Laws Of Motion

Question
CBSEENPH11016553

The motion of a particle of mass 50gm is given by x = 10t + 100t2. Find the force acting on the particle.

Solution
Given, 
Mass of the particle, m = 50 gm

The equation of motion of particle is,
                 x = 10t + 100t2

Therefore acceleration of the particle is,
                straight a equals fraction numerator straight d squared straight x over denominator dt squared end fraction equals 200 straight m divided by straight s squared 
 
The force acting on the particle is,
F = ma = 0.05 x 200 = 10 N