-->

Laws Of Motion

Question
CBSEENPH11016549

A man weighing M kg, stands on a weighing machine inside a lift. What will be the reading of the machine if it:
(a) descends with acceleration a,
(b) ascends with an acceleration a and
(c) moves with constant velocity in upward direction?

Solution

(a)  
The true weight of body = Mg
Reaction of floor = R
Net force acting on the body is,
                     F = Mg  - R
If a is the acceleration with which lift moves downward, then
                     F = M a
∴                Ma = Mg - R
i.e.,               R = M(g - a)
Thus the apparent weight of the body is,
                 straight W subscript straight a space equals space straight R space equals space straight M left parenthesis straight g minus straight a right parenthesis
(b)
If lift is ascending in upward direction with acceleration a then
                 Ma = R - Mg
or               straight R space equals space straight W subscript straight a space equals space straight M left parenthesis straight g plus straight a right parenthesis 
(c)  
If lift moves with constant velocity then acceleration, a = 0. 
∴                straight W subscript straight a space equals space Mg
So, reading on the machine = Mg