Question
A man of mass M is standing in a lift accelerating down with acceleration a. What is the apparent weight of the man in the lift?
Solution
Mass of the man = M
Rate of acceleration of the lift = a m/s2
Acceleration due to gravity = g m/s2 which is acting downwards.
Weight of the man when the lift is moving downwards = M(g-a) kg
Rate of acceleration of the lift = a m/s2
Acceleration due to gravity = g m/s2 which is acting downwards.
Weight of the man when the lift is moving downwards = M(g-a) kg
