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Motion In Straight Line

Question
CBSEENPH11017855

Determine the speed with which earth have to rotate on its axis so that a person on latitude 600 would weigh 3/4th as such at present without rotation. Take equatorial radius as 6400 km. 

Solution

We have, 
mg' = mg - mRstraight omega squared space cos squared space straight lambda
That is, 
space space space space space 3 over 4 space mg space equals space mg space equals space mR space straight omega squared space cos squared space 60 to the power of 0

space space space space 1 fourth space mg space equals space straight m space straight R space straight omega squared space straight x space 1 fourth

rightwards double arrow space space space space space space space space straight omega space equals space square root of straight g over straight R end root space equals space square root of fraction numerator 9.8 over denominator 6400 space straight x space 10 cubed end fraction end root space

space space space space space space space space space space space space space space space space space space equals space square root of fraction numerator 98 over denominator 64 space straight x space 10 to the power of 6 end fraction end root space equals space fraction numerator 7 square root of 2 over denominator 8 space straight x space 10 cubed end fraction space

rightwards double arrow space space space space space space space space space straight omega space equals space space 1.24 space straight x space 10 to the power of negative 3 end exponent space rad divided by sec