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Motion In Straight Line

Question
CBSEENPH11017825

How much below the surface does the acceleration due to gravity become 70% of it's value on the surface of the earth. Radius of the Earth = 6.4 x 106 m. 

Solution

Here, 
g'/g = 70 / 100 = 7/10 ; d = ? 
Now, g' = g(1-d/R);
Therefore, 
fraction numerator straight g apostrophe over denominator straight g end fraction space equals space 1 space minus space straight d over straight R

7 over 10 space equals space 1 space minus space straight d over straight R

straight d over straight R space equals space 1 space minus space 7 over 10 space equals space 3 over 10

straight d space equals space fraction numerator 3 straight R over denominator 10 end fraction space equals space fraction numerator 3 space straight x space 6.4 space straight x space 10 to the power of 6 over denominator 10 end fraction

space space space space space space space space space space space space space space space space space space equals space 1.92 space straight x space 10 to the power of 6 space straight m