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Motion In Straight Line

Question
CBSEENPH11017783
Wired Faculty App

A satellite revolves in an orbit close to the surface of planet of density 5800 kg/ m3. Find the time period of revolution of the satellite.

Solution
The time period of the satellite revolving close to the surface of planet is,
                      straight T equals 2 straight pi square root of straight R cubed over GM end root 
where M is the mass of the planet.
The mass of planet, M equals 4 over 3 πR cubed straight rho 
Therefore,
 Time period, straight T equals 2 straight pi square root of fraction numerator 3 straight R cubed over denominator straight G cross times 4 πρR cubed end fraction end root space equals space square root of fraction numerator 3 straight pi over denominator Gρ end fraction end root
Here, we have
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Therefore,
 straight T equals square root of fraction numerator 3 cross times 22 over denominator 7 cross times 6.67 cross times 10 to the power of negative 11 end exponent cross times 5800 end fraction end root space equals space 4937 straight s, is the required time period of the revolution of satellite. 

Some More Questions From Motion in Straight Line Chapter

What is the most essential thing to study the motion of a body?

Can a body be always at rest in some frame?

Can a body be in motion in the frame associated with the body itself?

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

State which of the following are examples of one, two or three dimensional motion: 

(a) A kite flying in the sky.

(b) The earth revolving around the sun. 

(c) A train moving along the equator of the earth in clockwise direction. 

(d) Accelerated motion of a particle in a straight line.

Define distance.

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