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Units And Measurement

Question
CBSEENPH11017769

A rod of mass M and length L is hinged at point O. A small bullet of mass m hits the rod with velocity u as shown in figure. The bullet gets embedded in the rod. Find the angular velocity of system after impact.


Solution
Before the collision, the rod is at rest and bullet is moving with velocity u at a distance 0.8L.
Therefore angular momentum of system before impact is,

straight L subscript 1 space equals 1 third ML squared left parenthesis 0 right parenthesis plus mu left parenthesis 0.8 straight L right parenthesis

space space space space equals 0.8 space muL space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis

Bullet after hitting gets embedded into the rod.
Let straight omega be the angular velocity of the system after impact.
The angular momentum of system after impact is,
straight L subscript 2 space equals open square brackets 1 third ML squared plus straight m left parenthesis 0.8 straight L right parenthesis squared close square brackets straight omega space

space space space space equals space open square brackets 1 third straight M plus 0.64 straight m close square brackets straight L squared straight omega space space space space space space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis 
Using the law of conservation of momentum


space space space space space space space space space 0.8 space muL space equals space open square brackets 1 third straight M plus 0.64 straight m close square brackets straight L squared straight omega space

rightwards double arrow space space space space space space space space space space space space space space space space space straight omega equals space fraction numerator 0.8 muL over denominator open square brackets begin display style 1 third straight M plus 0.64 straight m end style close square brackets straight L squared end fraction space

space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 2.4 mu over denominator open square brackets straight M plus 1.92 straight m close square brackets straight L end fraction 
This is the angular velocity of the system after the impact.