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Motion In Straight Line

Question
CBSEENPH11017755

The Jupiter has a mass 318 times that of the earth and its radius is 11.2 times the earth’s radius. Estimate the escape velocity of a body from the Jupiter’s surface, given that the escape velocity from the earth’s surface is 11.2 km/s. Does your answer throw any light on why the atmosphere of the Jupiter contains light gases, mostly hydrogen, whereas the earth’s atmosphere has little of hydrogen gas?

Solution
Given,
Mass of Jupiter is 318 times mass of the Earth.
i.e.,                    Mj = 318M

Radius is 11.2 times the radius of the Earth.
                           Rj = 11.2Re

We know that the escape velocity of body from a planet is given by, 

                      straight v equals square root of fraction numerator 2 GM over denominator straight R end fraction end root 
space space space space straight v subscript straight j over straight v subscript straight e equals square root of fraction numerator 2 GM subscript straight j over denominator straight R subscript straight j end fraction cross times fraction numerator straight R subscript straight e over denominator 2 GM subscript straight e end fraction end root 
           equals space square root of straight M subscript straight j over straight M subscript straight e cross times straight R subscript straight e over straight R subscript straight j end root space equals space square root of fraction numerator 318 over denominator 11.2 end fraction end root 
rightwards double arrow   straight v subscript straight j space equals space straight v subscript straight e square root of fraction numerator 318 over denominator 11.2 end fraction end root space equals space 11.2 square root of fraction numerator 318 over denominator 11.2 end fraction end root space km divided by sec 
           = 59.7 km/sec 
Escape velocity for Jupiter is high as compared to the average speed of light gas molecules like hydrogen.
Therefore, atmosphere of the Jupiter contains light gases like hydrogen.