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Motion In Straight Line

Question
CBSEENPH11017752

Define escape velocity. Derive an expression for escape velocity. Find the value of escape velocity.

Solution

Escape velocity is the minimum velocity with which a body must be projected vertically upward so that it may just escape the surface of the Earth. 
Expression for escape velocity: 
Let a body of mass m be escaped from the gravitational field of the earth.
During the course of motion, let at any instant, body be at a distance r from the centre of the earth. 
                         
The gravitational force between body and the earth is,
                        straight F equals GMm over straight r squared dr  
Work done to raise the body by distance dr is, 
                     space space dW equals GMm over straight r squared dr 
Total work done, W in raising the body from the surface of the earth to infinity is, 
                             straight W equals integral subscript straight R superscript infinity GMm over straight r squared dr equals GMm open square brackets negative 1 over straight r close square brackets subscript straight R superscript infinity 
                         equals GMm open square brackets negative 1 over infinity plus 1 over straight R close square brackets

equals GMm over straight R 
If we throw the body upward with a velocity ve, then work done to raise the body from surface of the earth to infinity is done by kinetic energy.
Therefore, 
                   GMm over straight R equals 1 half mv subscript straight e squared 
rightwards double arrow                       straight v subscript straight e equals square root of fraction numerator 2 GM over denominator straight R end fraction end root space equals space square root of 2 gR end root  
rightwards double arrow                       straight v subscript straight e equals square root of 2 gR end root               ... (1) 
Substituting the values in equation (1), we have
g = 9.81m/sec and R = 6.4 x 106m
Escape velocity is given by, 
  straight v subscript straight e space equals square root of 9.81 cross times 6.4 cross times 10 to the power of 6 end root space

space space space space space equals space 11200 space straight m divided by straight s 

      equals 11.2 space km divided by straight s