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Motion In Straight Line

Question
CBSEENPH11017743
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What is the height of geostationary satellite from the surface of the earth?

Solution
Height of the geostationary satellite is, 
h= open parentheses fraction numerator straight T squared space straight R squared space straight g over denominator 4 space straight pi squared end fraction close parentheses to the power of begin inline style 1 third end style end exponent space minus space R
Put, R = 6.4 x 106 m
g = 9.8 m/s2 
T = 24 hrs = 24 x 60 x 60 s 
So, we get
h = 3.6 x 107 m = 36000 km.
The height of geostationary satellite from the surface of the earth is 36000 km.

Some More Questions From Motion in Straight Line Chapter

What is the most essential thing to study the motion of a body?

Can a body be always at rest in some frame?

Can a body be in motion in the frame associated with the body itself?

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

State which of the following are examples of one, two or three dimensional motion: 

(a) A kite flying in the sky.

(b) The earth revolving around the sun. 

(c) A train moving along the equator of the earth in clockwise direction. 

(d) Accelerated motion of a particle in a straight line.

Define distance.

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