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Units And Measurement

Question
CBSEENPH11017738

A solid cylinder rolls down the inclined plane from a height 0.6m. Find the speed of cylinder at the bottom.

Solution

Let,
m be the mass of the cylinder,
r be the radius of the cylinder,
v be the speed, and
ω be the angular velocity of cylinder at the bottom.
Therefore using the principle of conservation of energy,
 mgh space equals space 1 half space mv squared space plus space 1 half space Iω squared space
space
space space space space space space space space space equals space 1 half space mv squared space plus space 1 half open parentheses 1 half straight m space straight r squared space close parentheses space straight omega squared space

space space space space space space space space space equals space space 1 half space mv squared space plus space 1 fourth straight m space straight r squared space space straight omega squared

space space space space space space space space equals space 1 half space mv squared space space plus space 1 fourth straight m space straight v squared space

space space space space space space space space equals space 3 over 4 space mv squared space

rightwards double arrow space straight v space equals square root of 4 over 3 gh end root space

We space have space here comma space straight h space equals space 0.6 space

Therefore comma space

straight v space equals space square root of 8 space equals space 2 square root of 2 space straight m divided by straight s