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Motion In Straight Line

Question
CBSEENPH11017700

Two stars each of one solar mass (= 2 x 1030 kg) are approaching each other for a head-on collision. When they are a distance of 109km, their speeds are negligible. What is the speed with which they collide? The radius of each star is 104 km. Assume the stars to remain undistorted until they collide. (G = 6.67 x 10-11Nm2/kg2)

Solution

Let stack straight v subscript 1 with rightwards arrow on top space and space stack straight v subscript 2 with rightwards arrow on top be the velocities of two stars when they collide.
According to the law of conservation of momentum, 
               straight M stack straight v subscript 1 with rightwards arrow on top plus straight M stack straight v subscript 2 with rightwards arrow on top equals 0 
rightwards double arrow                       stack straight v subscript 1 with rightwards arrow on top space equals space minus stack straight v subscript 2 with rightwards arrow on top 
rightwards double arrow                       space straight v subscript 1 equals straight v subscript 2 equals straight v 
According to the law of conservation of energy, 
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We have  
Mass of the star, straight M equals 2 cross times 10 to the power of 30 kg 
Distance between the stars, straight r subscript 1 equals 10 to the power of 9 km equals 10 to the power of 12 straight m 
Radius of star, straight r equals 10 to the power of 4 km equals 10 to the power of 7 straight m 
The distance between two stars when they collide is,
               2r = 2 x 107m
∴ Speed with which the stars collide is given by, 

straight v equals square root of GM open square brackets 1 over straight r subscript 2 minus 1 over straight r subscript 1 close square brackets end root 
 equals square root of 6.67 cross times 10 to the power of negative 11 end exponent cross times 2 cross times 10 to the power of 30 cross times open square brackets fraction numerator 1 over denominator 2 cross times 10 to the power of 7 end fraction minus 1 over 10 to the power of 12 close square brackets end root 
 equals 2.58 cross times 10 to the power of 6 space straight m divided by straight s