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Units And Measurement

Question
CBSEENPH11017639

Show that torque produced by force on the body is equal to product of the force and perpendicular distance of line of action of force from the axis of rotation or it is equal to the product of radial distance of point of action of force from the axis of rotation and transverse component of force.

Solution

Consider a particle moving along the curve PQ under the influence of a force straight F with rightwards harpoon with barb upwards on top.
Let at any instant r, the particle be at A and its position vector is straight r with rightwards harpoon with barb upwards on top
 
Torque is given by, 
straight tau with rightwards harpoon with barb upwards on top space equals space r with rightwards harpoon with barb upwards on top space x space F with rightwards harpoon with barb upwards on top space

The space magnitude space of space torque space is comma space

straight tau with rightwards harpoon with barb upwards on top space equals space straight r space straight F space sin space straight ϕ space
where comma space straight ϕ space be space the space angle space between space
between space straight r with rightwards harpoon with barb upwards on top space and space straight F with rightwards harpoon with barb upwards on top. space

Now comma space

straight tau space equals space rF space sin space straight ϕ space

space space space equals space straight r space left parenthesis straight F space sin space straight ϕ right parenthesis space

space space space space equals space straight r space straight F subscript straight o

 
where,
Fϕ is transverse component of force.
Therefore, torque is equal to the product of radial distance and transverse component of force.

Also,
x   = τ Fsin ϕ
     = F(rsin ϕ)

 straight tau with rightwards harpoon with barb upwards on top  = Fd
Therefore, torque is equal to the product of the magnitude of force and perpendicular distance of line of action of force from the axis of rotation.