A particle of mass 2kg is moving with a velocity 4√10 m/s along the line y-3x+4=0. Find the angular momentum of the particle about the origin.

Solution

Here we have,
Mass of the particle, m = 2kg
Velocity, v = 4√10 m/s
Momentum of the particle,

straight p equals mv space equals 2 space cross times 4 square root of 10 space equals space 8 square root of 10 space Ns

The particle moves along line y-3x + 4 = 0.
Therefore, the perpendicular distance from origin to line =

fraction numerator 4 over denominator square root of left parenthesis 1 right parenthesis squared plus left parenthesis 3 right parenthesis squared end root end fraction space equals space fraction numerator 4 over denominator square root of 10 end fraction

straight L space equals space pd space space space space equals space 8 square root of 10 cross times fraction numerator 4 over denominator square root of 10 end fraction space space space space equals space 32 space Nms

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