Question
An electron of mass 9.1 x 10-31 kg revolves in a circle of radius 0.529 Å around the nucleus with speed of 2.2x106 m/s. Show that its angular momentum is equal to h/2 π, where h is Planck's constant.
Solution
Mass of the electron = 9.1 10-31 kg
Radius of the circle, r = 0.529
Speed = 2.2 x 106 m/s
The angular momentum of electron is,
L = mvr
= 9.1 x 10-31 x 2.19 x 106 x 0.527 x 10-10
= 1.0502 x 10-34 J s
Thus, L =