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Motion In Straight Line

Question
CBSEENPH11017514

If acceleration due to gravity at the surface of the earth is g then what is its value at depth d?

Solution
Let the earth be a homogeneous sphere of radius R with density ρ.
                   
 
The acceleration due to gravity at surface of the earth g is, 
   
                 straight g equals GM over straight R squared equals 4 over 3 πGρR
Let, at deptg 'd' the acceleration due to gravity be gd.
At a depth d, the gravity is only due to the mass of inner sphere of radius R-d. 
Therefore,
    straight g subscript straight d equals fraction numerator straight G left square bracket mass space of space sphere space of space radius space left parenthesis straight R minus straight d right parenthesis right square bracket over denominator left parenthesis straight R minus straight d right parenthesis squared end fraction 
       equals fraction numerator straight G begin display style 4 over 3 end style straight pi left parenthesis straight R minus straight d right parenthesis cubed straight rho over denominator left parenthesis straight R minus straight d right parenthesis squared end fraction 
     space space equals 4 over 3 πGρ left parenthesis straight R minus straight d right parenthesis 
   straight g subscript straight d space equals space 4 over 3 πGρR open parentheses fraction numerator straight R minus straight d over denominator straight R end fraction close parentheses 
        = straight g open parentheses 1 minus straight d over straight R close parentheses