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Motion In Straight Line

Question
CBSEENPH11017501
Wired Faculty App

Find the acceleration due to gravity on the surface of satellite of mass 2 x 1011kg and radius 25km.

Solution

Acceleration due to gravity, straight g equals GM over straight R squared
Here,
Mass, straight M equals 2 cross times 10 to the power of 11 kg
Radius, straight R equals 25 km equals 25000 straight m
       
Gravitational constant, straight G equals 6.67 cross times 10 to the power of negative 11 end exponent Nm squared divided by kg squared 

Acceleration due to gravity, 
 straight g equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 2 cross times 10 to the power of 11 over denominator left parenthesis 25000 right parenthesis squared end fraction 
   equals 2.13 cross times 10 to the power of negative 8 end exponent straight m divided by straight s squared 

Some More Questions From Motion in Straight Line Chapter

What is motion?

Is absolute rest or absolute motion possible?

What is the most essential thing to study the motion of a body?

Can a body be always at rest in some frame?

Can a body be in motion in the frame associated with the body itself?

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

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