What is the moment of inertia of ring of mass m and radius r about its diameter?

Solution

Consider two mutually perpendicular diameters AB and CD.
Now, using the theorem of perpendicular axes, we have
I_AB + I_CD = MR²
That is,
I_d + I_d = MR²

rightwards double arrow

I_d =

1 half space M R squared

The moment of inertia of ring about its diameter is 1/2 MR².

Some More Questions From Units and Measurement Chapter

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Units And Measurement

What is the moment of inertia of ring of mass m and radius r about its diameter?

Some More Questions From Units and Measurement Chapter

Can we use same units for different physical quantities?

Can we use different units to measure same physical quantity?

To measure a physical quantity X, the unit U is repeatedly used for n times. What is the magnitude of physical quantity?

Does the numerical factor in the quantitative measurement depend on the system of unit used?

Is one unit sufficient to measure a physical quantity?

Can a physical quantity have two or more units? Give example.

What are fundamental quantities?

How many fundamental quantities are there in mechanics?

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