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Motion In Straight Line

Question
CBSEENPH11017466
Wired Faculty App

The acceleration due to gravity at the surface of the earth is 9.8 m/s2. Find the density of the earth. (Take R = 6400km and G = 6.67 x 10-11 Nm2/kg2 ).

Solution
Acceleration due to gravity at the surface of the earth is,
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∴                 straight rho equals fraction numerator 3 straight g over denominator 4 πGR end fraction                   ... (1)
Here, we have
straight g equals 9.8 space straight m divided by straight s squared space space space space space space space space space space space straight R space equals space 6400 space km 
straight G equals 6.67 cross times 10 to the power of negative 11 end exponent Nm squared divided by kg squared 
So, putting the values in equation (1), we have

Density of Earth,
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     equals 5497 space kg divided by straight m cubed 

Some More Questions From Motion in Straight Line Chapter

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

State which of the following are examples of one, two or three dimensional motion: 

(a) A kite flying in the sky.

(b) The earth revolving around the sun. 

(c) A train moving along the equator of the earth in clockwise direction. 

(d) Accelerated motion of a particle in a straight line.

Define distance.

Define displacement.

Can magnitude of displacement be greater than distance travelled by particle?

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