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Motion In Straight Line

Question
CBSEENPH11017464
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Find the acceleration due to gravity at the surface of the earth in terms of density of the earth.

Solution
Acceleration due to gravity, g at the surface of the Earth is given by,
                         straight g equals GM over straight R squared 
Let straight rho be the density of body. 
The mass of the earth is, 
                        straight M equals fraction numerator 4 straight pi over denominator 3 end fraction straight R cubed straight rho
Therefore acceleration due to gravity in terms of density of the earth is, 
straight g equals fraction numerator straight G begin display style fraction numerator 4 straight pi over denominator 3 end fraction end style straight R cubed straight rho over denominator straight R squared end fraction equals fraction numerator 4 straight pi over denominator 3 end fraction ρRG 

Some More Questions From Motion in Straight Line Chapter

Can a body be always at rest in some frame?

Can a body be in motion in the frame associated with the body itself?

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

State which of the following are examples of one, two or three dimensional motion: 

(a) A kite flying in the sky.

(b) The earth revolving around the sun. 

(c) A train moving along the equator of the earth in clockwise direction. 

(d) Accelerated motion of a particle in a straight line.

Define distance.

Define displacement.

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