-->

Units And Measurement

Question
CBSEENPH11017459

Uniform and identical meter sticks are stacked, so that 20cm of each stick extends beyond the meter stick beneath as shown in figure. How many maximum numbers of sticks can be placed one over the other without making them to fall over?



Solution

The given metre sticks are identical in nature.
The centre of gravity of each stick is located at its mid-point as shown in the fig.

Let, n be the maximum numbers of sticks that can be placed one over the other without making them to topple. 
Let the edge O of the lowest stick S1, which is on the floor be the reference point.
The distances of centre of gravity of sticks S2, S3, S4......Sn are x2 = -30cm, x3 =-10cm, x4 = 10cm .........x = -30 + 20(n-2) = (20n -70)cm respectively.

Let m be the mass of each stick.
The position of centre of gravity of the sticks S2, S3, S4......Sn from the O is,
straight X space equals fraction numerator mx subscript 2 plus mx subscript 3 plus mx subscript 4..... mx subscript straight n over denominator straight m plus straight m plus straight m plus....... plus straight m end fraction space

space space space equals fraction numerator straight x subscript 2 plus straight x subscript 3 plus straight x subscript 4....... straight x subscript straight n over denominator straight n minus 1 end fraction space

space space space equals fraction numerator negative 30 minus 10 plus 10..... plus left parenthesis 20 straight n minus 70 right parenthesis over denominator straight n minus 1 end fraction space

space space space equals space left parenthesis 10 straight n minus 50 right parenthesis space cm

The condition for sticks not topple is that the position of CG of sticks S2, S3, S4......Sn should lie on left from edge of the S1.

i.e.,    X ≤ 0

rightwards double arrow     10n - 50 ≤ 0

rightwards double arrow      n ≤ 5

rightwards double arrow      n ≤ 5

Hence, at the maximum, five sticks can be stacked one over other.