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Units And Measurement

Question
CBSEENPH11017456

Discuss the motion of moon around the earth and derive its equation of motion.

Solution

Earth and the moon form a two-body system.
Let M and m be the masses of the earth and moon respectively.
Let straight r with rightwards harpoon with barb upwards on top be the position vector of moon with respect to earth.
Here, the force on the moon is gravitational force of earth and given by, 
                rightwards arrow for F of equals negative fraction numerator G M m over denominator r squared end fraction r with hat on top 
The equation of motion of moon is,
space F with rightwards harpoon with barb upwards on top space equals space straight mu space fraction numerator straight d squared straight r over denominator dt squared end fraction
where, μ is the reduced mass of the moon.
Reduced mass of the earth is given by,
              straight mu equals fraction numerator Mm over denominator straight M plus straight m end fraction
Substituting the values of straight mu space and space F with rightwards harpoon with barb upwards on top in the equation of motion, we get 
negative fraction numerator G M m over denominator straight r squared end fraction space stack straight r space with hat on top space equals space fraction numerator M m over denominator straight M plus straight m end fraction fraction numerator d squared r over denominator d t squared end fraction

rightwards double arrow space space space space fraction numerator d squared r over denominator d t squared end fraction space space equals space minus space fraction numerator straight G left parenthesis straight M plus straight m right parenthesis over denominator straight r squared end fraction space straight r with hat on top
This is the required equation of motion.