Find the gravitational force between two masses each of 1gm separated by a distance 1cm.

Solution

Gravitational Force, $space space straight F space equals space fraction numerator Gm subscript 1 straight m subscript 2 over denominator straight r squared end fraction$
Here, we have
Mass of the body, $straight m subscript 1 equals straight m subscript 2 equals 1 gm comma$
Radius, r = 1 cm
∴ Gravitational force,
$space space space straight F equals fraction numerator 6.67 cross times 10 to the power of negative 8 end exponent cross times 1 cross times 1 over denominator left parenthesis 1 right parenthesis squared end fraction equals 6.67 cross times 10 to the power of negative 8 end exponent dyne$

Some More Questions From Motion in Straight Line Chapter

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Motion In Straight Line

Find the gravitational force between two masses each of 1gm separated by a distance 1cm.

Some More Questions From Motion in Straight Line Chapter

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