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Motion In Straight Line

Question
CBSEENPH11017225

A body is released from rest at t = 0 from a height h from the ground. The body will be at

x from where it was dropped at two times i.e.  space space space space space space space space space plus square root of fraction numerator 2 straight x over denominator straight g end fraction end root space and space minus fraction numerator square root of 2 straight x end root over denominator straight g end fraction.

What is the significance of negative value of time?

                   




Solution
Using the second equation of motion, 
 straight x space equals ut plus 1 half gt squared
space space space equals space 1 half gt squared space space space space space space space space space space space space space space space space space space space space space open square brackets therefore space straight u equals 0 close square brackets

therefore space space space space space straight t space equals space plus-or-minus square root of fraction numerator 2 straight x over denominator straight g end fraction end root
't' is positive implies that body will be at  x after time  't' when the particle is dropped. 
If the particle was projected in upward direction from ground, then the particle would  be at x distance below from the highest point.