Question
A man standing on the edge of a cliff at some height throws ball straight up with initial velocity u and then throws another ball straight down with same initial speed. Which ball will hit the ground with a greater speed?

Solution
Velocity with the ball is thrown upwards = u
Velocity with which another ball is thrown down = u
Both the balls will hit the ground with the same velocity if air resistance is neglected.
Ball A:
Ball B:
Ball B is thrown upward with velocity u, therefore the first the ball rises up, after reaching the maximum height and it starts falling.
Let ball B rise up by x.

That is, the ball B rises by
.
Now ball B has to fall by a total distance of
.
Let vB be the velocity of ball B, when it reaches the ground.
Velocity with which another ball is thrown down = u
Both the balls will hit the ground with the same velocity if air resistance is neglected.
Ball A:

Ball B:
Ball B is thrown upward with velocity u, therefore the first the ball rises up, after reaching the maximum height and it starts falling.
Let ball B rise up by x.

That is, the ball B rises by
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Now ball B has to fall by a total distance of

Let vB be the velocity of ball B, when it reaches the ground.
