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Motion In Straight Line

Question
CBSEENPH11017216

Show that if a body retards at the rate numerically equal to distance travelled, then the distance travelled by the body before comes to rest is numerically equal to velocity at the time at which the body starts retarding.

Solution

Here we have, 
Body retards at a rate of distance travelled. 
That is, 
         a = -s 
v dv over dx space equals negative space s
rightwards double arrow space minus straight v space dv space equals space straight s space ds space space space space space space space space space space space space space space space space space... space left parenthesis 1 right parenthesis
Let the velocity of the body when it starts retarding be v0 and come to rest by travelling the distance s.

Integrating both sides of (1) between initial and final limits, 
space space space space space integral subscript straight v subscript straight o end subscript superscript 0 straight v. space dv space equals space integral subscript 0 superscript straight t straight s space straight s space

rightwards double arrow space space space space right enclose negative straight v squared over 2 end enclose subscript straight v subscript straight o end subscript superscript 0 space equals space right enclose straight s squared over 2 end enclose subscript 0 superscript straight t space

rightwards double arrow space space space space space space space space space straight v subscript straight o squared over 2 space equals space straight s squared over 2

rightwards double arrow space space space space space space space space space space space space space straight v subscript straight o space equals space straight s