What is the minimum amount of energy released in the annihilation of electron positron pair?

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Solution

Energy released during the annihilation of e^–, e⁺ pair is,

space space space space space space straight E equals 2 straight m subscript straight c straight c squared

equals 2 cross times 9.1 cross times 10 to the power of negative 31 end exponent cross times left parenthesis 3 cross times 10 to the power of 8 right parenthesis squared space straight J

equals fraction numerator 2 cross times 9.1 cross times 9 cross times 10 to the power of negative 15 end exponent over denominator 1.6 cross times 10 to the power of negative 13 end exponent end fraction MeV

equals 1.02 space MeV

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