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Work, Energy And Power

Question
CBSEENPH11017138
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What is the work done in dragging a body in horizontal direction by a force of 40N acting at angle 60° with horizontal through a distance of 24m?

Solution

Given that,
Force space acting comma space straight F space equals space 40 straight N Angle space made space by space the space body space with space the space horizontal comma space straight theta equals 60 degree Distance space moved space by space the space body comma space straight S equals 24 straight m
So, work done by the body is given by, 
            straight W equals straight F with rightwards arrow on top times straight S with rightwards arrow on top space equals space FScosθ
           space space space space space equals 40 cross times 24 cross times c o s 60 equals 480 straight J

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