Question
If the kinetic energy of a moving body increases by 300 %, then by what percentage the momentum will increase?
Solution
Let the kinetic energy of the body be K and momentum of the body be p.
K.E = 1/2 mv2 ... (1)
Given that the K.E increases by 300 %.
That is,
Increasing factor of K.E = 300X 1/100 = 3
Therefore, the new K.E, K' = K + 3K = 4K
Now, equation (1), we have 
Initial momentum, p = m v = m X 
That is, the momentum will increase by 100%.
