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Work, Energy And Power

Question
CBSEENPH11017194

A running man has half the kinetic energy that a boy of half his mass has. The man speeds up by 1.0m/s and then has the same kinetic energy as the boy. What were original speed of man and boy?

Solution
Let M and m be the mass of man and boy respectively.
Let, the original velocities of man and boy be v1 and v2  respectively.
we have,
Mass of the boy is half of mass of man.
That is,  m equals M over 2
And K.E of the boy is equal to the K.E of man.
i.e.,         K subscript m a n end subscript space equals space 1 half K subscript b o y end subscript
i.e.          1 half M v subscript 1 squared equals open square brackets 1 half open parentheses straight M over 2 close parentheses straight v subscript 2 squared close square brackets
rightwards double arrow                   straight v subscript 2 equals 2 straight v subscript 1                       ...(1)
When the speed of man increases by 1m/s, the kinetic energies of both man and boy become same.
i.e.      1 half straight M left parenthesis straight v subscript 1 plus 1 right parenthesis squared equals open square brackets 1 half open parentheses straight M over 2 close parentheses straight v subscript 2 squared close square brackets 
rightwards double arrow           2 left parenthesis straight v subscript 1 plus 1 right parenthesis squared equals straight v subscript 2 squared                 ...(2)
From eqn. (1) and (2),
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On solving we get,
Velocity of the man, straight v subscript 1 equals 2.41 space straight m divided by straight s
Velocity of the boy, straight v subscript 2 equals 2 straight v subscript 1 equals 4.82 space straight m divided by straight s