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Work, Energy And Power

Question
CBSEENPH11017188

The velocity of a car is doubled. What is the ratio of percentage increase in kinetic energy to the percentage increase in momentum?

Solution
Let u be the initial velocity of the car.
On doubling its velocity,
Final velocity becomes 2u.
Therefore,
Initial momentum, p subscript i space equals space m u
Final momentum,space space space p subscript f equals 2 m u
Percentage increase in momentum is,
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#6 {main}</pre>
Initial kinetic energy, K subscript i equals 1 half m u squared 
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#6 {main}</pre>
Percentage increase in kinetic energy is,
space space fraction numerator 4 K minus K over denominator K end fraction cross times 100 % space equals space 300 %
Ratio of percentage is, 
Now, 
fraction numerator Percentage space increase space in space straight K. straight E. over denominator Percentage space increase space in space momentum end fractionequals fraction numerator 300 % over denominator 100 % end fraction equals 3