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Motion In Straight Line

Question
CBSEENPH11017174

A car starts from rest and acquires a velocity of 12m/s in 5 sec. Calculate the acceleration and distance moved.

Solution

Here,
Initial velocity, u = 0
Final velocity, v = 12m/s
Time taken to acquire the velocity, t = 5s
Using the equation, we have
                    v = u + at
therefore space space space space space space a equals space fraction numerator straight v minus straight u over denominator straight t end fraction equals fraction numerator 12 minus 0 over denominator 5 end fraction equals 2.4 space straight m divided by straight s
and space space space straight s space equals space fraction numerator straight v squared minus straight u squared over denominator 2 straight a end fraction

space space space space space space space space space space space space space equals fraction numerator left parenthesis 12 right parenthesis squared minus left parenthesis 0 right parenthesis squared over denominator 2 cross times 2.4 end fraction space

space space space space space space space space space space space space space equals 30 straight m
where, a is the acceleration of the moving car, and 
s is the distance moved by the car.