Question
Show that during a free fall - total energy (Kinetic + Potential) remains constant.
Solution
Let a body of mass m be dropped from point A at a height h from the ground.
At point A:
The kinetic energy is,

Potential energy is,

∴ Total energy at point A,
...(1)
At point B:
Let in time t, the body reach point B after falling through a distance x.
Let v be the velocity of body at B.
Now,
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Kinetic energy at B is,
∴
Kinetic energy at ground is,
Potential energy is,
∴ Total energy at point ground is,
Since total energy at A = total energy at B + total energy at ground.
Therefore total energy during free fall remains conserved.

At point A:
The kinetic energy is,

Potential energy is,

∴ Total energy at point A,

At point B:
Let in time t, the body reach point B after falling through a distance x.
Let v be the velocity of body at B.
Now,
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Kinetic energy at B is,

Potential energy is,

∴ Total energy at point B is,
...(2)
At ground:
On reaching the ground, let velocity of the body be V.

∴ Total energy at point B is,

At ground:
On reaching the ground, let velocity of the body be V.
∴

Kinetic energy at ground is,

Potential energy is,

∴ Total energy at point ground is,
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Since total energy at A = total energy at B + total energy at ground.
Therefore total energy during free fall remains conserved.