Question
A body of mass 0.24Kg is tied with a string of length 70cm and made to revolve in a circular orbit of radius 70cm on the top of a horizontal table. The table is rough and has coefficient of friction 0.25. Find the work done by tension force in the string and by the force of friction in making one complete revolution.
Solution
Work done by tension:
We know that the tension force is always perpendicular to instantaneous displacement.
Therefore, the work done by tension force is zero.
Work done by force of friction:
We have,
Force,
Distance travelled,
Therefore,
Work done by the tension force in the string is,
We know that the tension force is always perpendicular to instantaneous displacement.
Therefore, the work done by tension force is zero.
Work done by force of friction:
We have,
Force,
Distance travelled,
Therefore,
Work done by the tension force in the string is,
